(t)=16t^2+320

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Solution for (t)=16t^2+320 equation: 



(t)=16t^2+320

We move all terms to the left:

(t)-(16t^2+320)=0

We get rid of parentheses

-16t^2+t-320=0

a = -16; b = 1; c = -320;
Δ = b2-4ac
Δ = 12-4·(-16)·(-320)
Δ = -20479
Delta is less than zero, so there is no solution for the equation

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